AnsweredAssumed Answered

Define interrupt handler as weak

Question asked by giso on Feb 22, 2017
Latest reply on Feb 23, 2017 by B.H

I need to define my own interrupt handler. Cube not not generate the ISR as weak so everytime I regenerate the code with cube, I have to modify the code to hide the interrupt handler generated by cube.


Would it be possible to define them as weakß