On 11-12-2007 at 11:24, Anonymous wrote:
I intend to use a LD1117S33CTR voltage regulator to provide the 3.3V MCU. This regulator is rated at 1%. Does this mean that I can also expect 1% precision off the ADC?
On 11-12-2007 at 13:19, Anonymous wrote:
I only need whatever current the STM VDDA pin takes plus about 200uA for other analog stuff. The LM4132 looks like an interesting part. The quiescent current is a little high (60uA)-- ideally I would like something under 30uA. I wonder how much current VDDA on the STM32 requires? Maybe I could put the VDDA regulator in shut down mode when the processor is in standby mode. If I could do this the quiescent current would not matter.
On 12-12-2007 at 18:15, Anonymous wrote:
Can I run VDD (digital) from 3.6V and supply VDDA (analog) with 2.5 volts from a precision reference. Is it possible to have VDD and VDDA at different voltages like this? I can't find anywhere how much current VDDA will take but I'm sure it can't be more than a few mA.
I'm spending the majority of the time in standby mode therefore it would be nice to maybe switch off VDDA when in standby mode. Is this possible?
[ This message was edited by: togrady on 13-12-2007 14:08 ]
no the part will be destoyed if |VDDA-VDD| >.05 volts, see table 4
On 08-01-2008 at 10:12, Anonymous wrote:
Quote: no the part will be destoyed if |VDDA-VDD| >.05 volts, see table 4
Are you sure that VDDA cannot be different from VDD, I had a look at the datasheet and can see that |ΔVDDx|
In the STM32 Reference Manual, in table 65 they mention the following:
2.4V ≤ VDDA ≤ VDD (3.6V)
You mean table 48?
Analog power supply equal to VDD and
2.4 V ≤ VDDA ≤ VDD (3.6 V)
The first line says they must be equal, the second that VDDA must be above 2.4V
Retrieving data ...