AnsweredAssumed Answered

problem in calling timer interrupt routine

Question asked by patil.rajiv on Dec 30, 2014
Latest reply on Dec 31, 2014 by Clive One
I am using timer2 and I am trying to generate an interrupt from it, so according to vector table the TIM2 ID is 44 so i  am defining an interrupt routine as

__interrupt(44) void TIM2_IRQHandler()
so why is it not jumping to the routine upon interrupt?