Hello,First of all, the max voltage allowed on TS942 is 10V. It means that Vccp-Vccn = 10V, thus you could supply the TS942 with Vccp=5V and Vccn = -5V or Vccp=10V and Vccn=0V.A supply voltage of +/-9Volt will be above AMR, indeed the op-amp will have a supplied voltage of 18V.
The TS942AIDT has ESD diodes internal that provide a direct path from Vcc- to Vcc+.
If the current is limited (<20mA), then Vcc(= Vccp - Vccn) =+9V or -9V will not be a destructive condition .Please note that the device is not operating while reversed supplied.
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