Hello
I am using the L6494(14PIN) as a driver for a high and low side FET in a half bridge arrangement. My DC volts can be anything from 120Vdc to 220Vdc. and current up to 17A
Is there anyway to determine the breakdown mechanism if I do not momentarily switch the bottom driver on to charge the bootstrap capacitor.?
If I do not switch the bottom driver on first so that the bootstrap capacitor is charged and accadently turn the top driver on first, it destroys the driver and fets.
I have wired in the L6498 (8PIN) and this does not behave the same way. I can always make sure of the sequence under normal conditions but under a fault condition this could not be guaranteed and an expensive call out could follow.
Is there possibly another way to guarantee the bootstrap capacitor gets charged ?
thanks
