2026-04-15 6:13 AM - last edited on 2026-04-15 6:17 AM by mƎALLEm
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手册上写着在高分辨率模式下功耗 90 µA,在低功耗模式下功耗低于 1 µA。可是我用示波器串联电阻抓出来的功耗接近1MA,并且未使用MCU配置传感器时功耗就已经接近这个值了。传感器通过开发板的3.3V接口进行供电。电路图如下所示,哪里存在问题呢?
Translation:
The manual states that the power consumption is 90 µA in high-resolution mode and less than 1 µA in low-power mode. However, the power consumption I measured with an oscilloscope using a series resistor is close to 1 mA, and this value is already close to the power consumption even without configuring the sensor using the MCU. The sensor is powered through the development board's 3.3V interface. The circuit diagram is shown below. Where is the problem?
Solved! Go to Solution.
2026-05-11 6:54 AM
需要说明的是,我已经把中断引脚悬空
2026-05-11 6:54 AM
需要说明的是,我已经把中断引脚悬空
2026-05-11 8:20 AM
If you are powering the LIS2DW12 directly from VUSB (~5 V) you have likely damaged or destroyed the IC because, according to the data sheet (Table 4), the maximum input voltage is 3.6 V.
Maybe you should try again using a 3 V battery instead.
2026-05-11 1:53 PM
It should be noted that I have left the interrupt pin floating. == Translation
2026-05-11 1:55 PM
如果您能将文本翻译成论坛上使用的标准语言(英语),那就太好了。您想要得到答案,为别人翻译会很麻烦。
2026-05-11 7:40 PM
Sorry, I didn’t explain clearly. I am using TTL to USB, and I only use the 3.3V and GND pins of the TTL to USB, which is equivalent to supplying 3.3V power to the LIS2DW12.