cancel
Showing results for 
Search instead for 
Did you mean: 

VSSA VDDA and analog / digital ground separation. What's best?

d4
Associate III

Hello,

I have a mixed signal application in development, a home energy monitor, and following on from the recent PCB version's test results on the effects of noise, and after reading this article, I've decided to separate my digital and analog ground, which makes A LOT of sense.

I have the 100-pin package, STM32F303VE, it has VSSA and VDDA pins. Shall I connect VSSA to analog ground, while connecting VSS (digital) to the digital ground?

I ask because the Analog Dialogue article states that the digital ground of an MCU must be connected to analog ground, for the sampling architecture to have the same reference as the analog elements of the circuit.

However I have reason to believe the sampling architecture of the stm32f3 is connected to VSSA, and therefore can be separated.

I could route all VSS pins to 2-way solder jumpers and could report back with a noise test results on connecting all VSS to either DGND or AGND. If someone already has experience here, I would appreciate the time.

Cheers,

Dan

10 REPLIES 10
TDK
Guru

I always tie VSSA directly to VSS at the package and get good performance out of the ADC. If getting the absolute best analog performance is important to you, then you might want to spend time looking at it, but for me at least there's enough to do that spending a lot of effort getting another bit of resolution from the ADC isn't a priority.

I think the more important factor is the quality of your voltage reference and how well isolated VDDA is from noise on VDD.

If you feel a post has answered your question, please click "Accept as Solution".
d4
Associate III

Okay, so the voltage reference is coming from a dedicated REF19x IC, it can handle a useful amount of capacitance on it's output and the input to VREF therefore looks solid. It appears the REF19x can deliver the current to supply VDDA also – could be a good idea then.

I wonder what would happen if VDDA is slightly higher than VDD, could happen with the tolerance of the regulators, the main one is an MCP1501.

Peter BENSCH
ST Employee

The appnote AN2834 is a good source of information regarding ADC and influencing factors:

https://www.st.com/resource/en/application_note/cd00211314.pdf

Good luck,

/Peter

In order to give better visibility on the answered topics, please click on Accept as Solution on the reply which solved your issue or answered your question.
TDK
Guru

The reference manual lists some rules for this scheme. Probably other info in there as well.

0693W000001rITfQAM.png

If you feel a post has answered your question, please click "Accept as Solution".
d4
Associate III

A useful manual that, I'll have to re-read with an eye to the subject at hand.

Seems Vdd can go higher than Vdda in terms of maximum ratings. It's the impact on accuracy I'd have to find out.

0693W000001rJ4bQAE.png

f303xE datasheet

d4
Associate III

the ap. note says again and again it's the ratio of VREF+ to the analog input pin that defines the value acquired.

I'll have to get a solder jumper off vdda to test if it prefers the main regulator or the ref19x.

I'll set them both to 3.3V, regardless of the tolerances making an unfavourable condition, seems the chip can handle it.

d4
Associate III

Any idea what the effect might be if Vdd is slightly higher than Vdda? got a 0.4% difference at 3.3V = 13.2mV difference possible with my comps, MCP1501 is the main reg. I doubt it's important but I'll have to check now :\

d4
Associate III

which manual is this?

I can't find that first condition in mine.

Peter BENSCH
ST Employee

The acquired value is of course depending on the ratio of VREF and analog input. It depends on your reqirements, if you either do:

  • a ratiometric measurement, i.e. VREF+=VDD, or
  • an absolute measurement, i.e. VREF+ = known reference

Ratiometric measurements are often used with resistive sensors, like e.g. NTC, because it keeps the system cost low (no external VREF needed) and at the same time, the reference voltage changes in the same ratio as VDD. It is a ratiometric measurement if the 3.3V you are talking about is supplying both VDD and VDDA.

Absolute measurements rely on a reference voltage (internal or external) and require some calculation to get the final value.

As the datasheet states you should definitely avoid higher voltages at VDD compared to VDDA, while 400mV is the maximum difference.

It depends on your settings and hardware, if the resulting measurement showing some difference.

/Peter

In order to give better visibility on the answered topics, please click on Accept as Solution on the reply which solved your issue or answered your question.