Posted on March 07, 2017 at 15:21HI:
I'm using the eDesignSuite to design an AC/DC transformer that has a secondary at 135 vdc, 40 Iavg. The listed turns ratio is 550.26m .... why the 'm' ?
Here are the transformer details:
Transformer Specifications:
fsw: 60 kHz - Isat ≥ 982 mA - Lp: 1.62 mH ± 15 % - leakage ≤ 3 %
Primary: Ipk 493 mA - Irms 201 mA - Iavg 123 mA
Aux: Ipk 158 mA - Irms 16 mA - Iavg 3 mA - Prim/Aux turn ratio 5.64
Out 1: Ipk 198 mA - Irms 73 mA - Iavg 40 mA -
Prim/Out 1 turn ratio 550.26 m
Out 2: Ipk 5.93 A - Irms 1.99 A - Iavg 1 A - Prim/Out 2 turn ratio 19.79
Out 3: Ipk 581 mA - Irms 88 mA - Iavg 20 mA - Prim/Out 3 turn ratio 9.49
Thanks!
Tom
Update: I see it now, just different than expected way for turns ratio.
