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Discrepancy in Datasheet STM32L011x3/4 - DoclD027973 Rev 5

Kurt Alber
Associate III
Posted on January 31, 2018 at 10:42

Hi!

At the manual script en.DM00206508.pdf (DoclD027973 Rev 5 -- Datasheet of STM32L011x3/4) at page 67/119 I have a misunderstanding. I wanted to look over the temperature stability over the HSI16 oscillator and the values in the table 38. (16MHz HSI16 oscillator characteristics) varies from the Figure 22 (HSI16 minimum and maximum value versus temperature - MSv34791V1).

The STM32 is supplied with VDD=3.0V and VDDA=3.0V and int the table 38 the values for a ambient temperature TA=-10°C to 105°C are -4% to 2%. At the other side in Figure 22 with (minimum and maximum values) is a 3V operated chip over -45°C to 125 °C with a maximum variation of the oscillator of 1%.

Please help me clarify this discrepancy.
1 ACCEPTED SOLUTION

Accepted Solutions
Amel NASRI
ST Employee
Posted on January 31, 2018 at 16:01

Hi

kal

‌,

The figure 22 is added to show that HSI16 min and max values don't depend much on VDD values. Being at 3.6V or 1.65V, min values or max values don't show a big variation.

The curve provided for 3V is for typical values. That is why you don't see the big variation as it may be concluded from the table '16 MHz HSI16 oscillator characteristics'.

-Amel

To give better visibility on the answered topics, please click on Accept as Solution on the reply which solved your issue or answered your question.

View solution in original post

1 REPLY 1
Amel NASRI
ST Employee
Posted on January 31, 2018 at 16:01

Hi

kal

‌,

The figure 22 is added to show that HSI16 min and max values don't depend much on VDD values. Being at 3.6V or 1.65V, min values or max values don't show a big variation.

The curve provided for 3V is for typical values. That is why you don't see the big variation as it may be concluded from the table '16 MHz HSI16 oscillator characteristics'.

-Amel

To give better visibility on the answered topics, please click on Accept as Solution on the reply which solved your issue or answered your question.